5j^2-12j+4=0

Solution for 5j^2-12j+4=0 equation:

Simplifying
5j2 + -12j + 4 = 0

Reorder the terms:
4 + -12j + 5j2 = 0

Solving
4 + -12j + 5j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(2 + -5j)(2 + -1j) = 0

Subproblem 1
Set the factor '(2 + -5j)' equal to zero and attempt to solve:

Simplifying
2 + -5j = 0

Solving
2 + -5j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5j = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5j = 0 + -2
-5j = 0 + -2

Combine like terms: 0 + -2 = -2
-5j = -2

Divide each side by '-5'.
j = 0.4

Simplifying
j = 0.4
Subproblem 2
Set the factor '(2 + -1j)' equal to zero and attempt to solve:

Simplifying
2 + -1j = 0

Solving
2 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1j = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1j = 0 + -2
-1j = 0 + -2

Combine like terms: 0 + -2 = -2
-1j = -2

Divide each side by '-1'.
j = 2

Simplifying
j = 2
Solution
j = {0.4, 2}